Maswali ya Biashara ya Crypto, Pochi na Blockchain
Maswali na majibu ya kawaida yanayojumuisha biashara ya cryptocurrency, pochi na maarifa ya blockchain, pamoja na maelezo na maudhui ya majibu yanayohusiana.
- 01
Je, minyororo ya miamala 26 ambayo haijathibitishwa imepigwa marufuku na pochi katika Bitcoin Core 31.0?
Unaweza kuwa na mnyororo mrefu zaidi ya miamala 25 ambayo haijathibitishwa kwenye mempool, lakini pochi bado inatekeleza kikomo cha mnyororo wa miamala 25. Kutoka kwa kuendesha bit...
Teknolojia - 02
What does it mean that the security of Bitcoin public keys and 256-bit ECDSA is 128 bits?
What does it mean that the security of 256-bit ECDSA, and therefore Bitcoin keys, is 128 bits? I mean, if I have approximately 2^256 possible points on the elliptic curve (thus pos...
Usalama na hatari - 03
Receiving donation on a bitcoin address and security issues of reusing the same address
For a blog that only receives occasional small amounts you probably shouldn't worry too much about it. However, if you plan to scale up, here are some things to consider: One issu...
Usalama na hatari - 04
How can vulnerabilites in bitcoin be responsibly reported?
Information on current (ie, not past/public/resolved) security issues should be sent to the private [email protected] mailing list. The SourceForge list is now...
Usalama na hatari - 05
Is 24 words seed safer than 12 words in terms of bruteforcing the private key
Regardless of whether you have a passphrase or not 12 words is just as secure as 24 words because the resulting public key will still require 2^128 iterations to compute its privat...
Usalama na hatari - 06
Brassard-Høyer-Tapp (BHT) Algorithm and Bitcoin (BIP360)
Grover's is related and some considerations were discussed here on Stackexchange, too. We could design a black box function to break both P2PKH and P2SH (and P2WSH, etc.) addresse...
Usalama na hatari - 07
How do you derive the private key from two signatures that share the same k value?
ECDSA signatures are pairs (r,s) where r=(k*G).x mod n, and s = (m + r*x)/k mod n, where x is the secret key, k is the random nonce, and m is the message. If you have two s values...
Usalama na hatari